If y=e(1/2)log(1tan2 x), then (dy/dx) is equal to (A) (1/2)sec2x (B) sec2x secx tanx (D) e(1/2)log(1tan2 x) Check Answer and Solution for aboveTo ask Unlimited Maths doubts download Doubtnut from https//googl/9WZjCW `Solve x dy/dxy=y^2logx`Given that dy/dx=log10 (xy), y(0)=1, find y(02) using modified Euler's method MATHEMATICS3 question answer collection
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If y=log(1-x^2/1 x^2) find dy/dx
If y=log(1-x^2/1 x^2) find dy/dx- Share with your friends Share 3 Follow 8 Manbar Singh, Meritnation Expert added an answer, on Manbar Singh answered this We have, y = log x cos x x 2 1 x 2 1 Let y = u v where u = log x cos x and v = x 2 1 x 2 1 Now, y = u v ⇒ dy dx = du dx dv dx 1 Let u = log x cos x ⇒ log u = cos x log log x ⇒ 1 u Find dy/dx (x) 1/2 (y) 1/2 = (a) 1/2 Mention each and every step Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day Kindly Sign up for a personalised experience
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Stack Exchange network consists of 179 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers Visit Stack ExchangeSee the answer See the answer done loading Use logarithmic differentiation to find dy/dx y= (x1) (x2)/ (x1) (x2) The answer is dy/dx= 2 (x^22)/ (x1)^2 (x2)^2 I just need to see stepbystep how to solve Thank you!Solution for dy dx?
To ask Unlimited Maths doubts download Doubtnut from https//googl/9WZjCW `(1x^2)dy/dx=1y^2`If y = sec –1 cosec x cosec –1 sec x sin –1 cos x cos –1 sin x , then dy/dx is equal to If y = sin (log e x) then x 2 d 2 y/dx 2 xdy/dx is equal to If y = sin1 (5x12√(1x 2))/13, then dy/dx is equal to If y = sin1 (x/2) cos1 (x/2), then the value of dy/dx is If y = sin 2 α cos 2 (αβ) 2 sin α sin βGiven y = a log x Note that derivative for ln x is 1/x (And I think this has been misunderstood by some users here as "derivative for log x is 1/x") From the given function y above, => y = a * (ln x / ln 10) Based on constant multiple rule of de Continue Reading Related Answer Subhasish Debroy , Former SDE at Bharat Sanchar Nigam Limited
We start with the function y = l n ( x) First use exponentiation with the base e to get rid of the log, a common manipulation with log equations, e y = x (*) Now take the derivative of each side, remembering to use the chain rule on ey, because y is a function of x d d x e y = d d x x and If y log 1 cos x 1 cos x 1 2 Show that dy dx cosec x mention each and every formula and minute details Mathematics TopperLearningcom h7b68mm> Starting early can help you score better!Why create a profile on Shaalaacom?
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Calculus Find dy/dx y=1/ (x^2) y = 1 x2 y = 1 x 2 Differentiate both sides of the equation d dx (y) = d dx ( 1 x2) d d x ( y) = d d x ( 1 x 2) The derivative of y y with respect to x x is y' y ′ y' y ′ Differentiate the right side of the equation Tap for more stepsUse logarithmic differentiation to find dy/dx (x 1) (x 2) y = x > 2 (x 1) (x 2)' dy x dx = Find f' (x) and f' (c) Function f (x) = (x5 5x) (2x4 5x – 3) Value of a = C= 0 f' (x) = = x f' (c) = = x Find an equation of the tangent line to the graph at the given point (x 2)2 (y 3)2 = 37, (1, 3) y = x Circle GD 6 2 197 2 0Question If log(x 2y 2)=2tan −1( xy ) then dxdy = A x−yxy B xyx−y C xy1 D None of these Easy Solution Verified by Toppr Correct option is A) Differentiating both sides of the given relation with respect to x, we get, dxd log(x 2y 2)=2 dxd tan −1( xy ) x 2y 21 × dxd (x 2y 2)=2× 1(y/x) 21 × dxd ( xy ) x 2y 21 dxd (x 2) dxd
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Solved Use Logarithmic Differentiation To Find Dy Dx Y Chegg Com
If y = log((1 x^2)/(1 x^2)), then dy/dx = A 4x^3/1 x^4 B 1/4 x^4 C 1/4 x^4 D 4x^3/1 x^4 ← Prev Question Next Question The correct question is If then prove that Given the equation We have to prove that Given the equation Differentiating with respect to 'x' , we get Multiplying the above equation by , we get Now, Differentiating again with respect to 'x' that is the second order differential of the given function, we get Multiplying the above equation by we get,1 Inform you about time table of exam 2 Inform you about new question papers 3 New video tutorials information
If Xy Log X Y 1 Prove That Dydx Y X 2y X Y X Xy 2 X Y
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Y = e x log x Use product rule dy/dx = e x log x e x (1/x) = e x (log x 1/x) Hence option (2) is the answer Was this answer helpful?Find d2y/dx2 where y=log(x^2/e^2) y=log(x 2 /e 2 ) diff wr to x , we get dy/dx=1/(x 2 /e 2 ) (2x/e 2 ) =2/x diff wr to x again d 2 y/dx 2 =2/x 2 ThankDy = y 2 cosx y2 cot x dx (1 –log y ) sin x 1 – log y Answer 3 y cot x 1logy 8 If xy = e x –y, then dy/ dxis equal to 1 y 2 x (1 log x)2 (1 logx)2 3 log x 4 none of these ( 1 logx)2 8 Solution Given that xy = e x –y y log x = (x –y) log ee y
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Best Answer This is the best answer based on feedback and ratings y= (x1) (x2)/ (x1) (x2) apply logarithms we get if y= log(xroot x21)2 show that (1x2) d2y/dx2 xdy/dx =2 Maths Continuity and DifferentiabilityIf y=logex((x1/x2))1/2, then (dy/dx) equal to (A) 7 (B) (3/x2) (3/(x1)) (D) None of these Check Answer and Solution for above question from
If Y Log 1 X 2 1 X 2 Then Dy Dx Is Equal To
If Y Log 1 2t 2 T 4 X Tan 1 T Find Y Teachoo
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